8 Nov 2021
Problem 29b
Page 280
Section 4.3: Derivatives and Shapes of Curves
Chapter 4: Applications of Differentiation
Textbook ExpertVerified Tutor
8 Nov 2021
Given information
Given:-
critical points which we found in part (a).
Step-by-step explanation
Step 1.
As we found in part one the function has two critical numbers.
we conclude that the given function has one local minimum value because it changes decreasing interval at 
and starts increasing at that point.
so we found the local minimum:
also, we know at 
the function does not change its interval of increasing.
so, the given function has no local maximum value.
Single Variable Calculus: Early Transcendentals
4th Edition, 2018
Stewart
ISBN: 9781337687805
Solutions
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