Textbook ExpertVerified Tutor
26 Oct 2021
Given information
Note that the given derivative of the function 
by explicit differentiation is 
and by implicit differentiation is 
.
Step-by-step explanation
Step 1.
Take the derivative of the function that is by explicit differentiation it is and by implicit differentiation it is .
Now, to verify that the derivative obtained implicitly and explicitly is the same substitute the value of 
from the function in the value of derivative found by implicit differentiation.
Take the function .
Now, isolate the value of on the left-hand side of the above equation.
Subtract 
on both sides of the equation .
Single Variable Calculus: Early Transcendentals
4th Edition, 2018
Stewart
ISBN: 9781337687805
Solutions
Chapter
Section
- Problem 1a
- Problem 1b
- Problem 1c
- Problem 2a
- Problem 2b
- Problem 2c
- Problem 3
- Problem 4
- Problem 5
- Problem 6
- Problem 7
- Problem 8
- Problem 9
- Problem 10
- Problem 11
- Problem 12
- Problem 13
- Problem 14
- Problem 15
- Problem 16
- Problem 17
- Problem 18
- Problem 19
- Problem 20
- Problem 21
- Problem 22
- Problem 23
- Problem 24
- Problem 25
- Problem 26
- Problem 27
- Problem 28
- Problem 29a
- Problem 29b
- Problem 30a
- Problem 30b
- Problem 30c
- Problem 31
- Problem 32
- Problem 33
- Problem 34
- Problem 35
- Problem 36
- Problem 37a
- Problem 37b
- Problem 37b
- Problem 37c
- Problem 37d
- Problem 38a
- Problem 38b
- Problem 39
- Problem 39
- Problem 40
- Problem 41
- Problem 42
- Problem 43
- Problem 44
- Problem 45
- Problem 46
- Problem 47a
- Problem 47b
- Problem 48a
- Problem 48b
- Problem 48c
- Problem 49
- Problem 50
- Problem 51
- Problem 52a
- Problem 52b
- Problem 53
- Problem 54
- Problem 55a
- Problem 55b
- Problem 56