24 Oct 2021
Problem 15
Page 111
Section 2.3: Calculating limits using limit laws
Chapter 2: Limits and Derivatives
Textbook ExpertVerified Tutor
24 Oct 2021
Given information
The given expression is:
Step-by-step explanation
Step 1.
Substitute 0 for in the given expression.
Therefore, it can be noticed that the value of the expression for is not defined.
The fifth law of limit is , if .
Evaluate the value of .
In the given expression it can be noticed that .
That is the denominator of the given expression becomes 0.
Therefore, the fifth law of limit cannot be applied to evaluate the limit.