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The table below shows the means and standard deviations of the survival times (in days) of some cancer patients who were treated with the same medication. Use these statistics to answer the question below. Which type of cancer patients       had the highest average survival time?         had the lowest average survival time?         had the most consistent survival times (least variation)?         had the least consistent survival times (most variation)?         had a standard deviation that was almost equal to the mean?       Colon cancer patients’ survival times were less / more consistent than stomach cancer patients’ survival times.         On average, ovarian cancer patients’ survival times differed from 884.3 days by about  .       A breast cancer patient had a survival time of 1000 days. Was this within one standard deviation of the mean or was it further out? Enter "within" or "further out".  

Problem Value: 3 point(s). Problem Score: 0%. Attempts (3 points) Consider the following small data set. Subject x y 1 6 19 2 8 17 3 1421 4 8 31 5 6 17 Find the linear correlation coefficient. r= 0.008161756 Help Entering Answers Preview My Answers Submit Answers

Chrome-Do Hemework Debra McQueen mathod.com/Student/PlayerHomework asphomeworkid-5513857048ouestionid-4fushed-truescid-57892958centerwinsyes BUSN 5760 QA SPRING 1 2020 APPLIED BUSINESS STATISTICS Debra McQuee Homework: Week 2 HW CH 4-6 Score:0 of 1 pt 5of 10 (4 complete) HW Score: 20%, 2 of 5.2.14-T EQuestion Hulp A manlachuing company regulaly conducts quality control checks at specifed penods on the products tmanufactures Hntoricaly the falle rate for LED lght bubs that the company manactures is 17% Suppose a random sample of 10 LED ght bulbs is selected Complete parts (a theough (d belo a What is the probablity that none of the LED light buibs are defective? The probability that none of the LED ight bulbs are defective is (Type an integer or a decimal. Round to four decimal places an needed) 1+ Less Σ An er in the anwer or and thentick.Check Enser your a acer

20 Applied x Homework secure openvelum.ecollege.com/course.html?courseld-157040798 HepiD-25acoeeftbf30f1930bdc2810010 BUSN 5760 QA SPRING 1 2020 APPLIED BUSINESS STATISTICS Debra McQueen a Homework: Week 2 HW CH 4-6 Save 10 of 10 ( completa) HW Score: 49.17%, 4.92 of 10 pts Score: 0.33 of 1 pt 6.2.13-T Question Help A particular manufacturing design requires a shaft with a diameter between 20.92 mm and 21 010 m. The mortaturing process yolds shalts with diameters normally distributed with a mean of 21.002 mm and a standard deviation of 0.005 mm Complete parts() through c). 3446 The proportion of shafts with diameter between 20.92 mm and 2100 mm i (Hound to four decimal places as needed) b. For this process what is the probability that a shart is acceptable? The probability that a shaft is acceptable is (Round to four decimal places as needed) More Enter your answer in the answer box and then click Check An 1

50 55 Question 8 (1 point) What is the probability that a random teacher from the High School is older than 45 years old (past their 45th birthday), P(x>4? Question 9 (1 point) What is the probability that a random teacher is between 35 and 55 years old, P(26)? Question 10 (1 point) What is the probability that a random teacher is exactly 40 years from their birth?

Homework 3: Problem 14 Problem Value: 3 point(s). Problem Score: 0%. Attempts F (3 points) Consider the following small data set. Subject x y 1 1621 2 3 28 3 6 18 4 10 24 5 14 26 Find the linear correlation coefficient. = Help Entering Answers Preview My Answers Submit Answers

Pe Chapter 6, Problem 12RE 2 Bookmarks Show all steps: ON Problem Consult Table 5.1, the 1992 abridged lite table for the United States (1) (a) What is the probability that a newborn infant will live to see his or her with birthday? (b) What is the probability that an individual who is 60 years old will survive for the next ten years? (c) Consider a man and woman who are married and who are both 60 years of age. What is the probability that both the woman and her husband will be alive on their 70th birthdays? Assume that the tivo events are independent (d) What is the probability that either the wife or the husband, but not both, will be alive at age 70? Step-by-step solution Step 1 of 4 A Refer to the 1992 abridged life table for United States. The probability that a newbom wil Ive to see his or her fifth birthday is, 0.00851 0.00172 = 0.01023 The required answer is 0.01023 Comments (2) Anonymous This is incorrect Anonymous I agree, this is wrong, the right answer is 0.98978 Submit 98 Chapter 5 Life Tobles TABLE 5.7 Abridged life table for the total population, United States, 1992 Stationary Population Of 100.000 Born Alive Age Interval Proportion Dying Yea Re Period of Life between Two Exact Ages Stated in Years (1) Proportion of Persons Alive at Beginning of Age Interval Dying during Interval (2) Number Living at Beginning of Age Interval (3) Number Dying during Age Interval In the Age Interval (5) In This and Alt Subsequent Age Intervals (6) torta 851 171 66.6 99,275 396,195 494,615 494,152 492.848 490,448 487.654 484,369 0-1 1-5 ....... 5-10 ...... 10--15 ... 15-20 ...... 20-25 ..... 25-30 ..... 30-35 ...... 35-40 40-45 45-50 50-55 55-60 60-65 65-70 70-75 ... 75-80 ..... 80-85 ..... 85 and over .. 480.187 0.00851 0.00172 0.00102 0.00121 0.00418 0.00528 0.00601 0.00765 0.01001 0.01305 0.01822 0.02799 0.04421 0.06800 0.10084 0.14673 0.21189 0.31480 1.00000 101 120 413 519 588 744 966 1247 1718 2591 3978 100.000 99.149 98.978 98.877 98,757 98.344 97.825 97,237 96,493 95.527 94.280 92,562 89.971 85.993 80,145 72,063 61,489 48,460 33,205 7.577.757 7,478,482 7,082.287 6,587,672 6,093.520 5.600,672 5.110.224 4,622,570 4.138.201 3,658,014 3.183.274 2.715,854 2.259,115 1.818,634 1.402.497 1,021,104 686,305 410,638 474,740 467,420 456,739 440,481 416,137 381,393 334.799 275,667 204,369 5848 8082 10.574 13.029 15,255 33,205 85 206,269 206,269 length of the interval. Therefore, 0-1 designates the one-year period of life fre until an individual's first birthday. Interval 1-5 represents the time from the fir day until the fifth birthday, a period of four years. All other age intervals span fr except for the last. This is an open-ended interval representing the entire peri beyond the 85th birthday. For the sake of convenience, abridged life tables-such as Table 5.1 most often in practice. Abridged tables display data in terms of five-year ag A complete life table would have an entry for each year, the complete lif culated for the U.S. population in 1979-1981 is shown in Table 5.8, at the chapter 13). In the United States, complete life tables are constructed eve

bf391118d9350bdcf42a10010 BUSN 5760 QA SPRING 1 2020 APPLIED BUSINESS STATISTICS Hi, Debra Sign Out tistics Homework BUSN 5760 QA SPRING 1 2020 APPLIED BUSINESS STATISTICS Debra McQueen Homework: Week 2 HW CH 4-6 Score: 0 of 1 pt 10 of 10 (7 complete) HW Score: 3167%, 3.17 of 10 6.2.13-T Question Help A particular manufacturing design requires a shalt with a diameter between 20 92 mm and 21010 mm. The manufacturing process yuld shalts with dametersom distributed with a mean of 21.002 mm and a standard deviation of 0.005 mm Complete parts (a) through ) a For this process what is the proportion of shafts with a diameter between 2012 and 2100 mm The proportion of shafts with diameter between 2002 mm and 2100 mmis 3446 Round to four decimal places as needed) b. For this process what is the probability that a shalt is acceptable? The probability that a shaft is acceptables (Round to four decimal places as needed) Enter your answer in the answer box and then click Check Answer mining acer

8. Find the probability that exactly 4 out 7 patients undergoing a certain surgical procedure will survive, if the probability of any patient surviving the surgery is .80.

M ANE 4352 - Manufacturing Simulation Homework No. 2 Spring 2020 Posted: Saturday, January 25, 2020 Due: Friday, February 7, 2020 Solution Posted: Monday, February 10, 2020, 11:59 pm Please work the following problems. Please show all of the steps in the determination of the solution. The point value of each problem is shown in the brackets behind the problem number 1.[25] Coefficient of restitution for a golf ball hitting the head of a golf club is an important parameter for golf club performance. (A higher value means more energy restored to the ball in flight, and therefore, a better drive with the golf club.) Restitution coefficients are measured for golf club X brand, with the following values given in Table 1. The golf club manufacturer states that the restitution meets or exceeds 0.82. Perform a test of hypothesis with a = 5%. Table 1 - Golf Club Brand X Coefficient of Restitution Experiment 0.8411 0.8582 0.8042 0.8191 0.8532 0.8730 0.8182 0.8483 0.8282 0.8125 0.8276 0.8359 0.8750 0.7983 0.8660 2. [25] A new manufacturing process is believed to have surface defects which follow a Poisson Distribution. The surface defects found in a sample of 30 sheets is contained in Table 2, below. Estimate the mean for this poisson Distribution and use a Chi Squared Goodness of Fit test to prove that Poisson is or is not a good fit. Table 2 - Poisson Distribution Data Number Found 03 6 2 3 4 6 or more 3. [25] Develop a LCG random number generator in a spreadsheet for the following constants: Z = 17, a = 31, c= 5, and m = 73. Generate 72 random numbers. Change the value of a to 23 and describe what happens. 4. [25] The data in Table 3, below is believed to come from an exponential distribution with a mean of 3. Use Kolmogrov-Smirnov procedures to prove or disprove this hypothesis at the a = 0.05% level. Table 3 - Data for Analysis with Kolmogrov-Smirnov 3 0.1 2.9 4.2 2.4 2.7 2.0 10 od 600 V 3.4 2.1 0.4 13 0.2 1.4 2.2 14 3.1 15 4.1 16 1.2 174.1 18 191.3 200.7 3.6

Chrome Do Homework Debra McQueen mathucomStudent/Player Homework aspx?homeworkid-551385704&questionid=4&flushed-trueeld:5739295¢erwinyes BUSN 5760 QA SPRING 1 2020 APPLIED BUSINESS STATISTICS Del Homework: Week 2 HW CH 4-6 Score: 0 of 1 pt | 6 of 10 (4 complete) HW Score 5.3.21 n wists to the website is 18 hout Complete al touch I below Assume that the number of new visitors to a website in one hour is distributed as a Posson random variable Theme a. What is the probability that in any given hour zero new visitors will the website? The pro y that new visitors wil niveis (Round to four decimal places as needed) and the 3

2. A ventilation perfusion scan is used to generate the probability of pulmonary embolism (PE) in patients. Based on the result of the scan, patients are classified as high prob- ability for PE, moderate probability for PE, and low probability for PE. Consider the following data, classified by patient's age: Age Scan 45-54 55-64 65-74 High Prob. for PE 13 15 20 Moderate Prob. for PE 14 18 Low Prob. for PE 25 20 31 Is a patient is selected at random, find the probability that a. The patient has a high probability for PE. [1] b. Th patient is at least 55 years of age. [1] c. The patient has a high probability of PE given that the patient is at least 55 years of age. [1] d. Are the events high probability for PE and at least 55 years of age independent? Justify your answer. [1]

Assume that the number of new visitors to a website has an average random hit rate of 2.9 unique Visitors every 4 minutes. What is the probability of getting exactly so unique visitors in a given hour!? Please show the calculation you make The formula for the Poisson distribution is IP (x=x) Axe-2/x! where x = 1,2,3

Week 2b - Ch3 Normal Distributions: Problem 3 Previous Problem List Next (1 point) The times for the mile run of a large group of male college students are approximately Normal with mean 7.13 minutes and standard deviation 0.78 minutes. Use the 68-95-99.7 rule to answer the following questions. (Start by making a sketch of the density curve you can use to mark areas on.) (a) What range of times covers the middle 95% of this distribution? (b) What percent of these men run a mile in less than 6.35 minutes? (a) from minutes to minutes (b) Note: You can eam partial credit on this problem. Preview My Answers Submit Answers You have attempted this problem 0 times. You have unlimited attempts remaining.

The probability that a patient arriving at an emergency unit needs to stay overnight is estimated to be 0.2. Assume the patients are admitted for overnight stay independent of each other. (a) The doctor has seen 5 patients in the first hour. What is the probability that more than 4 have to stay overnight? (b) A doctor starts her shift at 8PM. What is the probability that the first patient that will be registered for an overnight stay is the 4-th patient? (c) The emergency unit has a capacity of 5 beds. Each shift starts with all the beds free (patients are being transferred to a hospital by the end of the shift). Calculate the expected number of patients the doctor needs to see till all 5 beds are occupied.

50% of visitors in an exhibition will buy book A, 30% will buy book B, and 20% are just looking around the exhibition. Suppose that there are 10 visitors. a) Find the probability that if 10 visitors are in the exhibition, 4 will buy book A and 2 will buy book B. b) Find the expected number of visitors that buy book A. c) Find the expected number of visitors that buy book A, if 3 customers are looking around.

BUSI_1013 (Winter_2020): Learning Activity: Unit_2 Name: ID: Example 1: Sharpe Middle School is applying for a grant that will be used to add fitness equipment to the Bym. The principal surveyed 15 anonymous students to determine how many minutes a day the students spend exercising. The results from the 15 anonymous students are shown. O minutes; 40 minutes; 60 minutes; 30 minutes; 60 minutes; 10 minutes; 45 minutes; 30 minutes; 300 minutes; 90 minutes; 30 minutes; 120 minutes; 60 minutes; 60 minutes; 0 minutes; 20 minutes ** Lp = (p/100) (n + 1) (the p-th percentile formula to get the location). Determine the following five values. Min = Q1 = Med = Q3 = Max = If you were the principal, would you be justified in purchasing new fitness equipment? Is/are there any potential outlier (s)? IQR=Q3-Q1=. Lower Limit: Q1 - 1.5(IQR) =. Upper Limit: Q3 + 1.5(IQR)=. .. ............

A The number of visitors expected each day has a Poisson distribution. On Mondays, they expect 2 visitors and on Fridays they expect 3 visitors, but on other days of the week, they expect to receive 1 visitor per day. The numbers of visitors on separate days are mutually independent of one another. Find the probability that they receive at least 6 visitors in a five day week (Monday to Friday). che

eBook Assume that the traffic to the web site of Smiley's People, Inc., which sells customized T-shirts, follows a normal distribution, with a mean of 4.52 million visitors per day and a standard deviation of 720,000 visitors per day. (a) What is the probability that the web site has fewer than 5 million visitors in a single day? If needed, round your answer to four decimal digits. 0.7474 (b) What is the probability that the web site has 3 million or more visitors in a single day? If needed, round your answer to four decimal digits. 0.9826 (c) What is the probability that the web site has between 3 million and 4 million visitors in a single day? If needed, round your answer to four decimal digits. (d) Assume that 85% of the time, the Smiley's People web servers can handle the daily web traffic volume without purchasing additional server capacity. What is the amount of web traffic that will require Smiley's People to purchase additional server capacity? If needed, round your answer to two decimal digits. million visitors per day

In a certain clinic, visitors are diagnosed independently from one another. The probability that a visitor stays overnight is 0.2. i) The clinician has diagnosed 5 visitors in the first hour, what is the probability that more than 4 visitors will stay overnight. ii) A clinician's shift starts at 8:00 pm, what is the probability that the first visitor that will be registered for an overnight stay is the 4-th visitor? iii) The clinic has a capacity of 5 seats. Each shift starts with free seats. Calculate the expected number of visitors the clinician needs to see until all 5 seats are occupied.

Meeting Demands in a Fitness Center Individuals who become members of a fitness center do sọ for a variety of reasons, but one reason is often the availability of specialized facilities or equipment. Consequently, man- agement of the center is sensitive to the need for meeting member demand for equipment. At the same time, providing specific equipment requires funds to purchase and maintain it and space to house it. Indeed, because of financial and space constraints, making a decision to purchase a specific piece of equipment may mean that other equipment cannot be purchased. We consider a situation where management of a fitness center is evaluating whether it has enough stationary bicycles to meet the demand. There are currently five bicycles, and the demand in the early morning appears to exceed the capacity. Management believes members are frustated by the need to wait for bicycles in the period from 6:00 a.m. to 7:30 a.m.., add more bicycles. Data have been collected on equipment utilization between 6:00 a.m. and 7:30 a.m., and the data include arrival times and excercise times. The data represent observations of a stochastic process (actually several stochastic processes), and to simplify the modeling process, it is helpful to make assumptions about the underlying distributions for these random variables. Suppose that data are collected and reviewed with a goal of making reasonably simple assumptions about arrival rates. On the basis of the review, we assume that the rate of arrivals in the period 6:00 to 7:30 a.m. varies, with a peak arrival rate during the 30-minule period from 6:30 to 7:00 and lower rates before 6:30 and after 7:00. More specifically, we assume that arrivals have an exponential distribution with an average of 30 arrivals in the period from 6:00 to 6:30, an average of 45 arrivals in the period from 6:30 to 7:00, and an average of 20 arrivals in the period from 7:00 to 7:30, and the goal of the study is to determine whether it is economically desirable to Suppose that most of the members use the bicycles as part of an exercise program Let includes other activities, and we assume that the period of excercise time spent on the eycles is of fixed duration for all members: 8 minutes. Finally, we assume that if no bicycle DIe ailable when a member arrives, the member will wait for one to become available if IS e are three or fewer members waiting, but if there are four members already waiting, then the new arrival will leave. With these assumptions, we can simulate a single day as follows: We consider each ute of the 90-minute period, one minute after another, and we determine whether one amore of the members currently using a bike completes a session during that minute. If cach of the bicycles released becomes available for a new user. If there are members waiting, as many as possible are assigned bikes; those in line the longest are assigned first. Then, members arriving during that minute are considered, and if more than one member arrives in a minute, they are considered one after another. For cach arrival, we check whether there is a bicycle not being used by another person. If so, the member begins to use the hicycle. If there is no unused bicycle, then the member joins the queue of people waiting for a bicycle if there are three or fewer people already waiting. If there are four people waiting, then the new arrival leaves. Note that the protocol for this simulation is for those who finish using a bicycle during a particular minute to do so before newly arrived members look for a bicycle. This is, of course, only one of several such assumptions that could be made. With the original task in mind, it is appropriate to record the total number of members who use the equipment each day, the total number who do not use it because there are four others waiting when they arrive, and the average waiting time for members who use the equipment. We assume that no member tries to use the equipment more than once a day. We will refer to members who leave without using a bicycle as disappointed. We repeat the simulation for 1000 runs, and we have the following results: Average number who try to use a bicycle = 94.60 Average number who are disappointed = 37.15 = 38.71% Average percent who are disappointed = 4.1 minutes Average waiting time The average percentage is computed by computing the percent disappointed each day and then averaging these percentages over the 30 days. This is not (necessarily) the same as the ratio of the average number who are disappointed to the average number who tried to use a bicycle. For the particular goal of this discussion, it is the average percentage of disappointed members that is of interest. In other situations, what should be noted might be the average number of disappointed members or the number (or percentage) of members who succeed in riding a bicycle. The questions that the managers of the center ask are 'What are the economic impli- cations of these results, and how do these results change if more respond to these questions, we look at the economics of the situation. Suppose the yearly membership dues for the facility are $360, or $30 per month. Also, suppose that members Ho use the stationary bikes do so ten times a month and that half of those who are dis- appointed more than three times in a month will cancel their membership. Finally, assume hat the yearly costs for purchase and maintenance of each stationary bicycle is $1200, or ipment is added?' To $100 per monthnner Can 200 CHAPTER 4 Simulation Models With these assumptions, we can investigate the economics of the current situation, Recall that the member's decision criterion results in half of the disappointed members dropping their membership if bicycles are unavailable more than 30% of the time-that is, unavailable more that three times a month, Let s be the probability that a member wll be disappointed when trying to use a bicycle on a random visit. Then, viewing multiple attempts to ride a bicycle as independent repetitions of a binomial trial with disappointment probability s, we find that the probability of four or more disappointments in a month (ten visits to the fitness center) is 1- (1 – s)10 – 10s(1 – s)º – 45s²(1 –s)% – 120s (1 - s)? (4.10) Half of the members with four or more disappointments will cancel, and the probability of this event is .5 times the expression (4.10). The economic cost to the center is $30 per month for each membership cancelled. Using the simulation results for the current situation. we estimate s as .387, so the probability that a random member who attempts to use the bicycles will cancel is ,2923, Also, we have the average number of members who attend each day-approximately 94.5 in the simulation leading to the data in Table 4.19. Thus, in this situation, the cost of cancellations is about $830 per month. This substantially exceeds the cost of installing another bicycle, and the next step is to use simulations to determine how many additional bicycles should be installed to maximize net income-that is, dues from continuing members less new costs. We repe 12 bicycles. We assume that the arrival schedules do not depend on the number of bicycles, an assumption that could be changed if there were data on which to base other assumptions about arrivals. Because the arrivals are given by a stochastic process, the average number of members who try to use bicycles varies slightly from one simulation to another. For the eight simulations reported here, that number was between 93.94 and 95.14. Using data derived from the simulations, we have the results summarized in Table 4.19. The cost and the simulation with additional stationary bicycles, using a total of 6 through revenue data in the table are monthly figures. Judging on the basis of the results shown in Table 4.19, management would achieve higher net revenue with more bicycles. The highest net revenue would be achieved for eight bicycles, although seven, eight, or nine bicycles would all give improvements of about 20% or more above the current level, Table 4.19 Percent of Disappointed Members Expected Cost of Cancellation Expected Net Cost Number of Probability of Cancellation of New Bicycles Bicycles Revenue 5. 38.7 .292 $830 $2006 6. 30.1 22.1 .177 504 $100 2231 .0804 228 2407 200 8. 15.9 .0301 86 2449 300 11.2 .0095 27 2408 2330 2234 2135 400 10 7.0 .0018 500 11 4.6 .0004 600 2.9 12 000 700 4. Repeat the analysis of the fitness center model when the assumption that half of the mem- bers who are disappointed more than three times a month will cancel their memberships is replaced by the assumption that (a)a30% of such members will cancel. CS (bar0% of such members will cancel. उ

50% of visitors in an exhibition will buy book A, 30% will buy book B, and 20% are just looking around the exhibition. Suppose that there are 10 visitors. a) Find the probability that if 10 visitors are in the exhibition, 4 will buy book A and 2 will buy book B. b) Find the expected number of visitors that buy book A. c) Find the expected number of visitors that buy book A, if 3 customers are looking around.

View History Bookmarks Window Help 2 ) 100% Mor mathal.com Problem Set - MAT-240-3865 Applied Statistics 20EW Do Homework Joshua Pearl MAT-240-R3865 Applied Statistics 20EW3 Joshua Pearl | 01/13/20 G Homework: 2-2 MyStatLab: Module Two Problem Set Score: 0 of 3 pts 3 of 15 12 complete HW Score: 6.15%, 40 Question Help Suppose the lengths of human pregnancies are normally distributed with 266 days and 16 days. Complete parts (a) and (b) below (a) The Sure to the right represents the normal curve with 266 days and 16 days. The area to the right of X=250 0.1908 Provide two interpretations of this area Provide one interpretation of the area using the given values. Select the correct choice below and in the answer boxes to complete your choice (Type Integers or decimals) A The proportion of human pregnancies that last less than days is The proportion of human pregnancies tha t more than 200 days is 0.1908 7.1.35 Provide a second interpretation of these in the given a Select the correct choice below and (Type integers or decimals) O A The probability that a randomly lected human pregnancy more than ay is O The probability that a randomly selected human regney las t days in the answer boxes to complete your choice on Click to select and enter your answers and then click Check Answer 2 coming

art 0 Help Me Solve This Question Help The following data represent the miles per gallon for a particular make and model car for six randomly selected vehicles. Compute the mean, median, and mode miles per gallon 25.1.29.9. 24.5 27.7.248, 31.8 x= 27.3 (Round to two decimal places as needed) Thus, the mean mileage per gallon for the six cars is 27 30 To find the median of a data set, first arrange the data in ascending order, then determine the number of observations, n, and finally, determine the observation in the middle of the data set. If the number of observations is odd, then the median is the data value that is exactly in the middle of the data set That is the n + 1 median is the observation that lies in the position. If the number of observations is even, then the median is the mean of the two middle observations in the data set. That is, the median is the mean of the observations that lie in the 5 position and the 5+1 position While either technology or the process described above can be used to find the median, in this problem, use technology. Determine the median M= (Round to two decimal places as needed) - vo 1) More Enter your answer in the answer box and then click Check Answer 3 parts remaining Clear All Check Answer Close

4 A large exhibit This weekend a mai data shows the a wh b If the capac exhibition center collected data about attendance at its exhibitions kend a major event is taking place at this centre and historical us that the average daily attendance for this type of event is 7850 ple with standard deviation 367 people What is the probability that more than 7000 people will try to attend the event on Saturday? se she capacity of the exhibition centre is 8500 people, what is the probability that the centre will reach its full capacity on Sunday? eta also shows that, on each day, the mean arrival time of the visitors after opening time is 155 minutes. Asuming that the arrival times of the visitare to the antw fallaw Poisson distribution, calculate the percentage of visitors that will arrive in the first 3 hours after the opening of the exhibition on Saturday

4 A large ex This weekend a major event is taking place at this centre and historical data shows that the average daily attendance for this type of event is 7850 people with standard deviation 367 people. collected data about attendance at its exhibitions pWhat is the probability that more than 7000 people will try to attend the event on Saturday? JE the capacity of the exhibition centre is 8500 people, what is the probability that the centre will reach its full capacity on Sunday? The data also shows that, on each day, the mean arrival time of the visitors after opening time is 155 minutes. Assuming that the arrival times of the visitors to the centre follow a Poisson distribution, calculate the percentage of visitors that will arrive in the first 3 hours after the opening of the exhibition on Saturday.

MAT-240-R3917 Applied Statistics 20EW3 Homework: 1-3 MyStatLab: Module One Problem Set Score: 0 of 5 pts 6 of 15 (5 complete) 3.1.13-T The following data represent the miles per gallon for a particular make and model car for six randomly selected vehicles. Compute the mean, median, and mode miles per gallon. 35.8, 26.3, 22.9, 25.6, 23.7, 28.4 D Compute the mean miles per gallon. Select the correct choice below and, if necessary, fill in the answer box to complete your choice. O A. The mean mileage per gallon is (Round to two decimal places as needed.) O B. The mean does not exist Click to select and enter your answer(s) and then click Check Answer.

11.1.3 Use the given graph to determine the value of the indicated limits. Af(x) 10- (a) lim f(x) 8- 6- (b) lim f(x) 4- x→-2 2- (a) Select the correct choice below, and if necessary, fill in the answer box to complete your choice. to 86 10 -4 O A. lim f(x) = X→-3 B. The limit does not exist. -8

QUESTION 5 5 points Save Answer Historically, the average waiting time spent on hold when phoning customer service for a particular bank was one and a half minutes. To determine whether the average time people were waiting had changed since they cut the number of customer service staff, the bank undertook a random sample of the waiting time recorded by 15 customers. The results are in the Y column (in seconds) of the data file P14.12.xls which can be found in a folder under the CML Quizzes tab. Assume that the test is performed at the 5% level of significance and that the distribution of waiting times is approximately normally distributed. 1. State the direction of the alternative hypothesis used to test whether average waiting time had changed. Type gt (greater than), ge (greater than or equal to), It (less than), le (less than or equal to) or ne (not equal to) as appropriate in the box. 2. Calculate the test statistic correct to two decimal places (hint: use Descriptive Statistics to calculated the standard deviation and sample mean). 3. Use KaddStat to determine the p-value for the test correct to two decimal places. 4. Is the null hypothesis rejected for this test? Type yes or no. 5. Regardless of your answer for 4, if the null hypothesis was rejected, could we conclude that the average waiting time is not 1.5 minutes at the 5% level of significance? Type yes or no. А в с 1 Ү X1 Х2 2 28 з 43 45 49 12.6 11.4 11.5 11.1 10.4 6. 57 68 9.6 74 9 81 82 86 101 112 114 119 10 11 12 134 126 143 152 143 147 128 119 130 135 141 123 121 129 135 9.8 8.4 8.8 8.9 8.1 7.6 7.8 13 14 15 1.4 124 6.4 16 17

Gradebook Log Out Forums Calendar 2020 > Assessment Kelsey Dos I Distributions Due in 2 hours, 59 minutes. Due Thu 01/23/2020 5:00 p Show Intro/Instructio Bonnaroo is a four-day music festival held every summer in Tennessee since 2002. Suppose the mean attendance for the festival is 80,287 people with a standard deviation of 3.502. Assume the number of people attending the festival is normally distributed. Use the Empirical Rule to answer parts a - c: a. Organizers of the festival can expect between and people to attend the festival 99.7% of the time. b. Approximately % of festivals will be attended by less than 83,789 people. c. If attendance this year is in the top 2.5%, then the attendance would be or more people. d. Mumford & Sons was one of the headline acts this year, and organizers anticipated a high attendance. An attendance of 95,000 people would be standard deviations the mean. (In the first box, you should enter the standardized value rounded to 3 decimal places. In the second box, enter one of the following two words: above or below.) Licens Points possible: 6 This is attempt 1 of 3. Submit

ork: Homework Section 3.1 2 of 9 (2 complete) an mean or sample mean as indicated. 3. 12, 19 ple mean for this data set. Select the correct choice below and fill in the answer bdx to complete your choice.

1) All the data are samples Given the folowing data sets: A: 16 46 35 46 38 36 40 30 29 37 44 56 50 47 23 40 30 27 38 47 58 40 46 38 19 49 50 B: 20 41 45 30 40 30 23 30 45 47 50 45 44 48 33 36 56 39 42 44 45 47 24 46 47 49 55 a) Find the five number summary for each data set. b) Draw the Box Plot for the data sets. c) Draw the histograms for each data set. d) Describe the distibution for each data set e) Find the means and standard deviations and distribution ) Find the stem and leaf for data set A

It appears that people who are mildly obese are less active than leaner people. One study looked at the average number of minutes per day that people spend standing or walking. Among mildly obese people, the mean number of minutes of daily activity (standing or walking) is approximately Normally distributed with 375 minutes and standard deviation 67 minutes. The mean number of minutes of daily activity for lean people is approximately Normally distributed with 523 minutes and standard deviation 107 minutes. A researcher records the minutes of activity for an SRS of 6 mildly obese people and an SRS of 6 lean people. (a) What is the probability that the mean number of minutes of daily activity of the 6 mildly obese people exceeds 420 minutes? (Enter your answer rounded to four decimal places.) probability: (b) What is the probability that the mean number of minutes of daily activity of the 6 lean people exceeds 420 minutes? (Enter your answer rounded to four decimal places.) probability:

A call center randomly selects and records customer calls. Call handling times in minutes for 20 calls are as follows: 6, 26, 8, 2, 6, 3, 10, 14, 4, 5, 3, 17, 9, 8, 9, 5, 3, 28, 21, and 4. Please calculate the 10th quartile, 90th quartile, median, Q1, Q3, sample mean, and sample standard deviation of call handling times.

The mean of the sample provided below is 7.5. Find x. 8.4 9 7.1 3.1 x Provide an exact answer.

Instructions For the following data set, find the mean, median, mode, midrange, variance, standard deviation, z-score for every data point, 63rd percentile, five number summary, and box plot. 63 52 79 41 79 75 64 50 88 56 60 82 49 58 90 40 60 58 73 77 56 58 48 65 83 81 71 68 71 47 97 56 52 46 76 65 47 43 82 42

The mean daily production of a herd of cows is assumed to be normally distributed with a mean of 32 liters, and standard deviation of 8 liters. A) What is the probability that daily production is than 10.9 liters? Answer= (Round your answer to 4 decimal places.) B) What is the probability that daily production is than 31.6 liters? Answer= (Round your answer to 4 decimal places.)

A customer service call center is studying how long its customers have to wait on hold when calling in. The hold times for 27 randomly selected calls are provided below. 4.62 8.94 2.38 4.95 0.5 0.91 7.35 5.6 7.09 2.2 6.56 8.08 0.12 7.75 6.55 8.31 6.18 4.44 2.43 4.76 1.12 7.32 3.53 8.97 0.78 9.94 8.69 Use the 1-Var Stats calculator function to find the median hold time for the calls in the sample. Round your answer to two decimal places.

Find the range of the sample provided below. 8.3 3 6.4 2.9 9.9 5.3 3.9 8.6 Provide an exact answer.

12. Use the sample data in #11 to answer the following questions: a) Find the sample mean and median, rounded properly. You may use 1-Variable Stats! sample median = b) Based on the values alone, what shape does this data set probably have? Why? C) If mean = median mode, what shape does a data set probably have? d) Write the entire five-number summary below, labeling each value: e) Using five number summary, draw a box plot below. Label each component with its numeric value. ) Find the IQR: 13. Suppose Test 1 has mean score of 76.2 and standard deviation of 4.3. Test 12 has mean score of 143.2 and standard deviation 8.7. You score 88.3 on Test 11 and 167.2 on Test 82. Which score should you send to Best University if you are trying to gain admission? Show work to prove your answer below. Which score? State z-score for Test #1: Z-score for Test #2: 14. Is your score for Test #2 (in problem w13) unusually high? Why or why not? BONUS: According to the 'outlier' formula, are there any outliers in the sample data in #11? values? Show calculations to justify in order to earn credit. so, which Scoring for Project: #1 (7), #2 (2), #3 (7), #4 (2), #5 (5), #6 (3,3,1), #7 (2,5,2), #8 (2,5,2,3), #9 (6,6, 2), #10 #11 (4, 2, 3), #12 (4, 2, 1, 2, 3, 1), #13 (4), #14 (2), Bonus (3). This project has a total of 103 points, including b