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17 Nov 2019

Use the following equation and chart to make a graph and obtain Ea in kJ/mol for this data. [My main problem is setting up and solving the equation mostly because I don't know where A is comming from and I don't know what to put.]

ln(k)=(-Ea/R)(1/T)+ln(A)

k=rate constant

Ea=activation energy

R=gas constant, 8.314 J/(mol K)

T=temperature in Kelvin

A=Arrhenius constant

T(Kelvin) k1(sec-1) k2(sec-1) k average(sec-1)
300 71 67 69.0
320 112 99 105.5
290 59 58 58.5

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Bunny Greenfelder
Bunny GreenfelderLv2
17 Jul 2019

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