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17 Nov 2019

Use the following equation and chart to make a graph and obtain E_{a} in kJ/mol for this data. [My main problem is setting up and solving the equation mostly because I don't know where A is comming from and I don't know what to put.]

ln(k)=(-E_{a}/R)(1/T)+ln(A)

k=rate constant

E_{a}=activation energy

R=gas constant, 8.314 J/(mol K)

T=temperature in Kelvin

A=Arrhenius constant

T(Kelvin) k1(sec^{-1}) k2(sec^{-1}) k average(sec^{-1}) 300 71 67 69.0 320 112 99 105.5 290 59 58 58.5

Use the following equation and chart to make a graph and obtain E_{a} in kJ/mol for this data. [My main problem is setting up and solving the equation mostly because I don't know where A is comming from and I don't know what to put.]

ln(k)=(-E_{a}/R)(1/T)+ln(A)

k=rate constant

E_{a}=activation energy

R=gas constant, 8.314 J/(mol K)

T=temperature in Kelvin

A=Arrhenius constant

T(Kelvin) | k1(sec^{-1}) | k2(sec^{-1}) | k average(sec^{-1}) |
---|---|---|---|

300 | 71 | 67 | 69.0 |

320 | 112 | 99 | 105.5 |

290 | 59 | 58 | 58.5 |

Bunny GreenfelderLv2

17 Jul 2019