Chapter 15, Section 15.6, Question 019 Find the flux of the vector field Upper F across sigma in the direction of positive orientation. Upper F left-parenthesis x comma y comma z right-parenthesis equals StartRoot x Superscript 2 Baseline plus y Superscript 2 EndRoot ⢠k ⢠where sigma is the portion of the cone r left-parenthesis u comma v right-parenthesis equals u ⢠c o s v ⢠i plus u ⢠s i n v ⢠j plus 10 ⢠u ⢠k with 0 less-than-or-equal-to u less-than-or-equal-to 4 ⢠s i n v comma 0 less-than-or-equal-to v less-than-or-equal-to pi. Enter the exact answer as an improper fraction, if necessary.
Chapter 15, Section 15.6, Question 019 Find the flux of the vector field F across Ï in the direction of positive orientation. F(x, y, z) - vx2+ y2k where ÏÇs the portion of the cone r(u, v)=ucos vi+usin vj+10uk with 0sus4sin v, 0svs Ï. Enter the exact answer as an improper fraction, if necessary. Click here to enter or edit your answer
