Reactions in solution follow all of the principles that we have previously mentioned. In solution, we have a new quantity, molarity (m). So, if we completely dissolve 6. 84 g of sucrose (c12h22o11) in enough water to make. 500. 0 ml of total solution (the volume of added water (solvent) will not necessarily equal. 1 l solution moles (of solute) = m x v(in l). In order to obtain moles of the dissolved species (solute), knowing the molarity, [c12h22o11] = where we use brackets [] to denote the concentration of a species in molarity units. Thus, [c12h22o11] denotes the concentration, in m, of c12h22o11 . it is easy to see that: Since we will mostly be dealing with aqueous solutions, which have approximately the same density, we will presume that when we mix two such solutions, the volumes will be additive. Below we give several examples of solution stoichiometry problems. Example # 1 - mass % and molarity.
