CHEM 1127Q Lecture 3: Chapter 3 Stoichiometry

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16 May 2018
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Chapter 3 Stoichiometry
Mole (mol.)(n)
It is the state of matter that contains as many objects(atoms, molecules, ions) as the
number of atoms is exactly 12 gms.
Avogadro’s number- 6.02X10^23
Examples. Calculate the number of C6H2O6 is equal to 6.02X10^23 atoms in
0.305 mol of C6H2O6 (sugar). 1 molecule of sugar has 6 oxygen atoms, 2
hydrogen atoms and 6 carbon atoms.
1 mol of C6H12O6 is equal to 6.02X10^23 C6H2O6 molecules
0.350 mol of C6H2O6 molecules
0.350(6.02x10^23 C6H2O6 molecules/1)+2.11x10^23 C6H12O6
1 molecule of C6H2O6= 12 H atoms
2.11X10^23 C6H12o6 molecules(12 H atoms/1 C6H12O6)= 2.53X10^23
Formula weight of C6H12O6
FWT of C6H12O6=6(A.w of C)+12(atomic weight of H)+6(Atomic weight) of
60(Atomic weight of 0).
6(amu)+12(amu)+6(16 amu)=180 amu
Molar mass
The mass in grams of 1 mol. of substances g/mol
Molar mass of C6H12O6 180 g/mol Mole mass/molar mass
Example: Calculate the moles of sugar (C6H12O6) in 5.380
NC6H12O6= (5.380 g/180 g/mol)= 0.02989 mol
Example: How many Cu atoms are in 3 g of a sample
3(6.02X10^23/1)= 2X10^24
Step 1: 3g/63.5=0.05 mol
Step 2: 1 mol of Cu atom= 6.02X10^23) cu atoms
( 0.05mol)(6.02X10^23)= 3X10^22
% composition
% element
(# of atoms of that element)(atomic weight)/ (Formula weight of
compound).
Example: Calculate % C, H and O in C12H22O11.
12(12)+1(22)+11(15)= 331
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%C=
(12)(12) amu/342)*100
%H=
(22)(1 amu)/342*100
%o=
(11)(16 amu)/342*100
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CHEM 1127Q Full Course Notes
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Document Summary

It is the state of matter that contains as many objects(atoms, molecules, ions) as the number of atoms is exactly 12 gms. Calculate the number of c6h2o6 is equal to 6. 02x10^23 atoms in. 1 molecule of sugar has 6 oxygen atoms, 2 hydrogen atoms and 6 carbon atoms. 1 mol of c6h12o6 is equal to 6. 02x10^23 c6h2o6 molecules. Fwt of c6h12o6=6(a. w of c)+12(atomic weight of h)+6(atomic weight) of. The mass in grams of 1 mol. of substances g/mol. Molar mass of c6h12o6 180 g/mol mole mass/molar mass. Example: calculate the moles of sugar (c6h12o6) in 5. 380. Example: how many cu atoms are in 3 g of a sample. Step 2: 1 mol of cu atom= 6. 02x10^23) cu atoms ( 0. 05mol)(6. 02x10^23)= 3x10^22. % element (# of atoms of that element)(atomic weight)/ (formula weight of compound). Example: calculate % c, h and o in c12h22o11.

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