CHEM 1127Q Lecture Notes - Lecture 6: Royal Aircraft Factory F.E.2, Iron(Iii) Oxide, Ammonium Sulfate

60 views3 pages
18 Sep 2017
School
Department
Professor
khangpham8412 and 36530 others unlocked
CHEM 1127Q Full Course Notes
44
CHEM 1127Q Full Course Notes
Verified Note
44 documents

Document Summary

Lecture 6 - chapter 3: composition of substances and solutions. Moles are # of molecules in a substance. Great for lab, not great for calculations. Moles and # of atoms are great for relating products to reactants. Mass = molar mass (g/mole) x n (# of moles) Molar masses - na = 22. 99 g/mole, cl= 35. 25 g/mole. Mm= ( 22. 99 g/mole * 1 mol) + ( 35. 25 g/mole * 1 mol) Molar masses - h = 1. 008 g/mole, o = 15. 99 g/mole, s = 32. 065. Mm= ( 1. 008 g/mole * 2 mol) + ( 15. 99 g/mole * 4 mol) + ( 32. 065. How to find moles from molecular formula g/mole * 1 mol) g/mole. C = 12. 011 g/mole, h = 1. 008 g/mole, o=15. 99 g/mole. = 1(14. 01 g/mole) +4(1. 008 g/mole) = 18. 042 g/mol. 2- = 1(32. 06 g/mol) +4(16. 00 g/mole) = 96. 06 g/mole. Total mass = mass cation + mass anion.

Get access

Grade+20% off
$8 USD/m$10 USD/m
Billed $96 USD annually
Grade+
Homework Help
Study Guides
Textbook Solutions
Class Notes
Textbook Notes
Booster Class
40 Verified Answers
Class+
$8 USD/m
Billed $96 USD annually
Class+
Homework Help
Study Guides
Textbook Solutions
Class Notes
Textbook Notes
Booster Class
30 Verified Answers

Related textbook solutions

Related Documents

Related Questions