CHEM 1050 Lecture Notes - Lecture 6: Process Function, Joule, Propyl Group
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1 Feb 2016
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You can never expect more (or less) energy from a chemical reaction by changing the method of performing the reaction (path is irrelevant). Work is not a state function, it is a path function. Energy involved in making a molecule from its elements. H f is the enthalpy change involved in making a mole of a compound from its elements. H f standard h @25 c / 1 atm. 2c + 3h2(g) + o2(g) c2h5oh(l) C6h12o6 + 6o2 6co2 + 6h2o (1 2 marks) *the ( - ) becomes irrelevant when you are taking energy * Calculate the energy (heat) you can get by burning 1. 0 g of glucose with that given by. Sucrose: c12h22o11 and its h f is 2221 kj/mol (don"t use this to solve) When given a h rxn value you can calculate h f of a product or reactant.
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