MATH 1007 Lecture Notes - Lecture 18: Cube Root, Radian

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Area with x as a funcion of y. A = int from c to d of [xright xlef]dy. To help us sketch this, use some key points. Recommended that we use: y = -3, -2, -1, 0, 1, 2, 3. Then sketch the two curves on the same plot. So the area in between the two funcions will be A = int -2 to 2 of [(4 y^2) (y^2 4)]dy. = int -2 to 2 of (8 2y^2)dy. = 8y (2y^3)/3 line from -2 to 2. We can do this same problem in a diferent way, like in last lecture. We can convert the whole funcion back to terms of x only if it is easy to do! Let s be a solid that has between x=a & x=0. Let a(x) be the area of the cross-secion in the plane p x through x & perpendicular to the x-axis, where a is a coninuous.

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